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Side-theorem of Euclid's b² = q · c und a² = p · c [Home] [Search] [Forum] [Links] [Contact] [Imprint] [Sitemap]
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Assertions b² = q · c and a² = p · c
Evidence Condition: Both hypotenuse sections p and q make the hypotenuse c. 1. b² = q · c b² = h² + q² (Theorem of Pythagoras, h² = p · q – Theorem of Euclid’s) b² = p · q + q² | q factored out b² = q · (p + q) (p + q = c, displayed shortly before) b² = q · c
2. a² = p · c a² = h² + p² (Theorem of Pythagoras, h² = p · q – Theorem of Euclid’s) a² = p · q + p² | p factored out a² = p · (q + p) (p + q = c, displayed shortly before) a² = p · c
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